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14
网球
4
预测游戏
论坛
Knoxville 2022  - 资格赛第一轮
Finished - 01:37
Cannon Kingsley Kingsley, Cannon [4]
7
7
0
0
0
Luke Johnson Johnson, Luke [Alt]
62
5
0
0
0
Court 2
16h00
Kirchheimer
d.
Wallart
↓
Kingsley
d.
Johnson
↓
Arribage
d.
Holmgren
↓
Hussey
d.
Rogers
↓
Montes-De La Torre
d.
Leote Prata
↓
唐纳德·杨
d.
Adams
All
Kin
Joh
Reduce
Winner shots
Unforced errors
Aces球
双误
一发成功率
% first serve points won
Break point saved
Return points won %
破發成功
Points won %
直落四分
Set points
賽末點
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
All
Joh
Kin
Expand
破發成功
Points won %
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
Set 1Set 2Set 3Set 4Set 5
Kin
Joh
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
Return
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
Return
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
Return
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
Return
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
Return
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
Return
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
XX
XX
Return
XX
XX
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
XX
XX
Return
XX
XX
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
XX
XX
Return
XX
XX
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
XX
XX
Return
XX
XX
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
XX
XX
Return
XX
XX
All Set 1Set 2Set 3Set 4Set 5
Kin
Joh
发球
XX
XX
Return
XX
XX
Kingsley
-
Johnson
Score
1h38
Set 2
1h38
7
-
5
7-6 7-5
+
1h35
6
-
5
7-6 6-5
+
1h30
5
-
5
7-6 5-5
+
1h27
4
-
5
7-6 4-5
+
1h24
3
-
5
7-6 3-5
+
1h21
2
-
5
7-6 2-5
+
1h17
2
-
4
7-6 2-4
+
1h12
1
-
4
7-6 1-4
+
1h08
1
-
3
7-6 1-3
+
1h05
0
-
3
7-6 0-3
+
1h01
0
-
2
7-6 0-2
+
0h58
0
-
1
7-6 0-1
+
0h57
Set 1
0h52
7
-
6
7-6
+
0h47
6
-
6
6-6
+
0h44
6
-
5
6-5
+
0h41
5
-
5
5-5
+
0h38
5
-
4
5-4
+
0h35
4
-
4
4-4
+
0h31
4
-
3
4-3
+
0h28
3
-
3
3-3
+
0h22
3
-
2
3-2
+
0h19
2
-
2
2-2
+
0h15
2
-
1
2-1
+
0h09
1
-
1
1-1
+
0h06
1
-
0
1-0
+
0h00
0
-
0
0-0
+
Jeu de service
Break
Inconnu
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